2.25t^2-11t-22=0

Solution for 2.25t^2-11t-22=0 equation:

2.25t^2-11t-22=0

a = 2.25; b = -11; c = -22;
Δ = b2-4ac
Δ = -112-4·2.25·(-22)
Δ = 319
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{319}}{2*2.25}=\frac{11-\sqrt{319}}{4.5}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{319}}{2*2.25}=\frac{11+\sqrt{319}}{4.5}
$